0=27k^2-k

Solution for 0=27k^2-k equation:

0=27k^2-k

We move all terms to the left:

0-(27k^2-k)=0

We add all the numbers together, and all the variables

-(27k^2-k)=0

We get rid of parentheses

-27k^2+k=0

a = -27; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-27)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-27}=\frac{-2}{-54}
=1/27
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-27}=\frac{0}{-54}
=0
$